Exception handling
 Source Code


// Contributed by - Anuj Das ( GC College, Silchar - @ Department of Computer Science )

import java.util.Scanner;

class ExceptionHandling {

static int divide(int x, int y) throws ArithmeticException {
	if(y == 0){
		throw new ArithmeticException();
	}
else {
	return x/y;
}
}
	public static void main(String[ ] args) {
	Scanner sc = new Scanner(System.in);
	try {
		System.out.print("Enter the value of x: ");
		int x = sc.nextInt();
		System.out.print("Enter the value of y: ");
		int y = sc.nextInt();
		int res = divide(x,y);
		System.out.println(x+" / "+y+" = "+res);
	}
	catch(ArithmeticException ae) {
		System.out.println("Arithmetic Exception:	Can not divide an Integer by Zero!!");
	}
	
	System.out.println("\nRemaining Code Executing....");
	}

}

cmd->  javac  ExceptionHandling.java
cmd->  java  ExceptionHandling

Enter the value of x: 5
Enter the value of y: 0
Arithmetic Exception:   Can not divide an Integer by Zero!!

Remaining Code Executing....